Дана таблица orders с колонками order_id

SQL для тестировщика

SELECT MONTH(order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

SELECT EXTRACT(MONTH FROM order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

SELECT DATE_TRUNC('month', order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

SELECT STRFTIME('%Y-%m', order_date) AS month, SUM(total_amount) AS total_order_amount
FROM orders
GROUP BY month
ORDER BY total_order_amount DESC
LIMIT 3;

Ответить на вопрос можно ниже ⬇️

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2.7K viewsMay 4, 2023 at 07:34

tg-me.com/sql_for_qa/89

Create: 2023-05-04
Last Update: 2025-07-02 20:00:56

Дана таблица orders с колонками order_id, customer_id, order_date, total_amount. Какой из следующих SQL запросов вернет топ-3 месяца с наибольшим количеством заказов?

A) SELECT MONTH(order_date) AS month, SUM(total_amount) AS total_order_amount FROM orders GROUP BY month ORDER BY total_order_amount DESC LIMIT 3;B) SELECT EXTRACT(MONTH FROM order_date) AS month, SUM(total_amount) AS total_order_amount FROM orders GROUP BY month ORDER BY total_order_amount DESC LIMIT 3;C) SELECT DATE_TRUNC('month', order_date) AS month, SUM(total_amount) AS total_order_amount FROM orders GROUP BY month ORDER BY total_order_amount DESC LIMIT 3;D) SELECT STRFTIME('%Y-%m', order_date) AS month, SUM(total_amount) AS total_order_amount FROM orders GROUP BY month ORDER BY total_order_amount DESC LIMIT 3;Ответить на вопрос можно ниже ⬇️

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Дана таблица orders с колонками order_id